NEGATIVE VOLTAGE GENERATOR
Every circuit needs perfect bias supply to perform well and some times. Integrated circuits or special components or output actuators need negative voltage.
Everyone needs a negative voltage rail
eventually, but most only have one rail supply. This project will show you how to
build a negative voltage generator that runs off a single rail supply voltage!
CONCEPT OF GENERATING NEGATIVE VOLTAGE
But using an oscillator, some diodes, and an ingenious arrangement
of capacitors, we
will exploit an impact called
capacitive coupling whereby a negative voltage near adequate to the availability voltage
can be generated... from a single rail supply!
CAPACITIVE COUPLING
Capacitive coupling is an impact where
a capacitor “attempts” to stay the voltage across its terminals constant. For
example, if each
side of a capacitor are at 0V and plate 1 is suddenly delivered to 10V,
the voltage on the
opposite plate will immediately begin to rise to 10V. The
same goes for the opposite: If the first plate is brought from 10V to 0V, then
the other plate will attempt to drop by 10V to keep the voltage across the
capacitor constant.
REMOVING POSITIVE VOLTAGE
As the input steps up from 0V to 10V,
the negative plate on C1 also will attempt to match thanks to capacitive
coupling. However, once the plate reaches 0.7V, D1 conducts and this prevents
the plate voltage from getting above 0.7V. Now with the positive plate at 10V and the
negative plate at 0.7V, the potential difference across the plate is 10 – 0.7 =
9.3V. When the positive plate drops rapidly from 10V to 0V, this 9.3V potential
difference must be maintained due to coupling. Therefore, the negative plate
drops to -9.3V. D1 cannot conduct as it is reversed biased, so this negative
voltage remains on the capacitor.
D2, however, is now conducting because the anode
(connected to C2 negative plate), is at a higher potential than the cathode
(connected to the -9.3V). Therefore, the voltage at the negative plate of C2
will reduce until D2 stops conducting. D2 will stop conducting once the voltage
drop across it becomes less than 0.7V. This will happen once the negative plate
of C2 becomes -9.3 - -0.7 = -8.6V.
But if an external device attempts to use the
negative voltage, it might very quickly be used up! This is because of
the relatively small sizes of C1 and C2 as well as the current limits of the
circuit driver. The solution is to attach an oscillator to
the input in
order that a negative voltage is consistently being
generated at C1, which keeps C2 topped up.
C2 is used as a de coupler for external devices
using the negative voltage to try and keep the value as constant as possible.
For our project, C1 will be a 10uF capacitor and C2 will be a 100uF capacitor.
COMPONENTS
• 555 timer Ic
• Diode(D1,D2)
• 10uF Capacitor (C1)
• 100uF Capacitor (C2)
• 5.6kΩ (R1)
• 47kΩ (R2)
• 100nF (C4)
• 10nF (C3)
• Assorted Wires
• Breadboard
• Supply voltage
COMPLETE CIRCUIT
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